Practical examples...
With an augmented chord, eg C-E-G# (Caug, or C+), the internal intervals are both major 3rds, but technically when you go from G# to the next C, that's a diminished 4th. However, the fact that it sounds like a major 3rd means you can view this chord as three different aug triads:
C+ = C-E-G#
E+ = E-G#-B#
Ab+ = Ab-C-E
All three chords sound identical - IOW they are "symmetrical" - which means they (it) can be used in 3 different situations.
Try this:
Code:
C+ F E+ A Ab+ Db
-0---1----|-0---0---|-0---1---
-1---1----|-1---2---|-1---2---
-1---2----|-1---2---|-1---1---
-2---3----|-2---2---|-2---3---
-3---3----|-3---0---|-3---4---
-----1----|(0)------|---------
Obviously the first shape in each pair is the same. The chord it resolves to suggests what it ought to be called (the augmented V chord of that key), but really it could be called anything.
The same applies to dim7 chords, which are a stack of 4 minor 3rds - or strictly speaking 3 minor 3rds and an augmented 2nd.
Code:
G# B D F G#
|_m3_|_m3_|_m3_|_a2_|
G#dim7 (vii chord of A harmonic minor) = G# B D F
Bdim7 (vii chord of C harmonic minor) = B D F Ab
Ddim7 (vii chord of Eb harmonic minor) = D F Ab Cb
Fdim7 = E#dim7 (vii chord of F# harmonic minor) = E# G# B D
Notice we have to spell them all differently (enharmonically) to reflect their origins, but these four chords all sound the same, so are essentially all the same chord in practice.
Try the following:
Code:
G#o7 Am Bo7 Cm Do7 Ebm E#o7 F#m
-1---0----|-1-------|-1---2-----|-1----2---|-------------------
-0---1----|-0---4---|-0---4-----|-0----2---|-------------------
-1---2----|-1---5---|-1---3-----|-1----2---|------------------
-0---2----|-0---5---|-0---1-----|-0----4---|--------------------
-----0----|-----3---|-----------|----------|-----------
----------|---------|-----------|----------|----------
Again, the first chord in each pair is the same, and it's the second one that suggests the correct name for the first one - because a dim7 is the normal vii chord in a minor key.
Try it with majors too:
Code:
G#o7 A Bo7 C Do7 Eb E#o7 F#
-1---0----|-1---0---|-1---3-----|-1---2---|-------------------
-0---2----|-0---1---|-0---4-----|-0---2---|-------------------
-1---2----|-1---0---|-1---3-----|-1---3---|------------------
-0---2----|-0---2---|-0---1-----|-0---4---|--------------------
-----0----|-----3---|-----------|---------|-----------
----------|---------|-----------|---------|----------
Still works, right? Even though the dim7 is not in the key of the 2nd chord.
In this case, you could see the dim7s as rootless V7b9s.
Eg G#o7 is like E7b9 (E G# B D F) without the E.